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the sum of  two numbers is 64 and sum of the first and twice the second is 88. what are the numbers

 

Sagot :

the answer of sum of 64 and 88 is152


Clairesviz
x+y=64
x+2y=88

and by elimination y=24 then lets substitute in to the eq. x+y=64

x+24=64
x=64-24
x=40 

Checking:
x+y=64                         x+2y=88
40+24=64                    40+2(24)=88
64=64                          40+48=88
                                    88=88