3 men went to a hotel to rent a room, the cost of the room was $30. Each man paid $10 to the bellboy and proceeded to there room. After a little while the bellboy realized that there was a special on rooms that night and the price for the mens room should have been $25. On his way to the mens room to give them back $5 he was puzzled how he was going to split $5 as he had no change. He decided he would give them each $1 and keep the remaining $2 for himself. So each man originally paid $10, but after the bellboy gave each man $1 back, each man paid $9. 9 x 3 = $27 plus the $2 the bellboy put in his pocket equals $29. The original price for the room was $30. Where did the last dollar go?

Question

Sulatnaderaviz Sulatnaderaviz

Math

Answered

3 men went to a hotel to rent a room, the cost of the room was $30. Each man paid $10 to the bellboy and proceeded to there room. After a little while the bellboy realized that there was a special on rooms that night and the price for the mens room should have been $25. On his way to the mens room to give them back $5 he was puzzled how he was going to split $5 as he had no change. He decided he would give them each $1 and keep the remaining $2 for himself. So each man originally paid $10, but after the bellboy gave each man $1 back, each man paid $9. 9 x 3 = $27 plus the $2 the bellboy put in his pocket equals $29. The original price for the room was $30. Where did the last dollar go?

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Anthonypinedaviz Anthonypinedaviz · Answer 1

The room rate was $25,the regular rate is $30,there would be a remaining $5 if the bellboy returned the $3 for each customer and he keep the remaining $2 it would still be $30,it is not supposed that the rate were $30,and returned the remaining $1 for each it does not mean that they had paid $9 each,but instead they had only paid $8.33 each and in $9 less $8.33 the difference is $.67 and that amount was in each customer so there were no amount to be found short...