Kris9710honeyviz
Answered

Ernest invested a part of his money at 16% annual interest.another part which is P50.000 more was invested at 18% annual interest. if the total annual income from the two investments was P94,000. how much was invested at each rate?

Sagot :

so its
[x+(0.16x)]+[(x+50)+(0.18(x+50))]=94000
2.34x+59=94000
2.34x=93941
x=40145.73

1st investment is 40145.73
2nd investment is 40195.73

Don't forget to say thanks if my ans helped you (: