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if n is the 1st integer and n+1 is the 2nd, show that the difference of their cube is always an odd number.

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Sagot :

Cheahjimmyviz
(n+1)³ =  n³ +3n².1+ 3n.1² + 1³  =  n³+3n²+3n + 1
n³+3n²+3n+1 - n³ =    3n²+3n+1
if n =0    the expression  3n²+3n+1         = 1
  n = 1                                                     =  7
  n= 2                                                     = 19
   n= 3                                                    = 37
   n= 4                                                    = 61
so it always a odd number