if three small squares are placed side by side in a row the result is a rectangle whose area in square meter is six times its perimeter in M. Find a side of one of the squares.

Sagot :

let x = length of one side of the square
 the area of the rectangle form =  3x* x =3x²
 the perimeter is    6x + 2x = 8x
 thus      3x² = 6 . 8x = 48x    / area is 6 times its perimeter
               3x²-48x = 0
             3x(x-16) =0
             x = 0 or x =16
the length of one side of the square is 16m