vol of cube = 8 cu ins thus length of 1 side of the cube = ∛8 = 2 Area of 1 surface = 2* 2= 4sq in therefore total surface area = 4* 6 = 24sq ins / 6 surfaces
[tex]volume = 8 \ in^3 \\ V= a^3 \\ where: \\"a" \ is \ the \ length \ of \ any \ edge \ of \ the \ cube. \\\\8=a^{3} \\a= \sqrt [3]{8 }\\a=2 \ in \\\\Surface \ Area \ of \ a \ Cube: \\\\ SA = 6 a^2\\\\SA=6\cdot 2^2=6\cdot 4=24 \ in^2[/tex]
