Lanchuiviz
Answered

27y^3-27y^2+9y-1
How will you factor this out?

Sagot :

Riza1viz
[tex]27y^3-27y^2+9y-1 =\\\\=3^3y^3-3^{3}\cdot y^2+ 3^2 \cdot y-1^3=\\\\= (3y)^3- 3\cdot 3^2y^2\cdot 1 +3\cdot 3y\cdot 1^2 -1^3=\\\\=(3y)^3- 3\cdot (3 y)^2\cdot 1 +3\cdot 3y\cdot 1^2 -1^3 =\\\\=(3y-1)^3\\ \\ \\(a-b)^3 = a^{3} -3a^2b +3ab^2-b^3 [/tex]