What is the solution set of |2x + 1| > 5?
A. {x|1 < x < –3}
B. {x|–1 < x < 3}
C. {x|x > 2 or x < –3}
D. {x|x < 2 or x > –3}



Sagot :

[tex]|2x + 1| > 5 \\\\ 2x+1 >5 \ \ \ or \ \ \ 2x+1 < -5 \ \ |\ subtract\ 1 \ to\ both\ sides\\\\ 2x >5-1 \ \ \ or \ \ \ 2x < -5 -1\\\\ 2x >4 \ \ \ or \ \ \ 2x < -6\ \ | \ divide \ both \ sides\ by\ 2 \\\\x>2 \ \ \ or \ \ \ x< -3 \\\\Answer : \ C. \ \left \{ x|x > 2 \ \ or \ \ x <-3 \right \} [/tex]