[tex]2x^2+7x+ 5 > 0 \\\\ (x + 1) \cdot (2 x + 5) >0\\\\ Find \ where \ it \ is \ equal \ to \ zero:\\\\ (x + 1) \cdot (2 x + 5)=0\\ \\x+1=0 \ \ or \ \ 2x+5 =0[/tex]
[tex]x=-1 \ \ or \ \ x=\frac{5}{2}=2.5 \\\\ When \ a \ is \ positive, \ the \ graph \ is \ concave \ up . \\ The \ function \ is \ more \ than \ zero \ on \ the \ interval : \ (-\infty ,-1)\cup (2.5,+\infty )[/tex]
