Taravelaviz
Answered

1. ) Find four consecutive odd integers such that the sum of the two largest integers subtracted from twice the sum of the two smallest integers is 96.

 

 

NOTE:

Please answer ASAP and explain briefly. No joking please!

Sagot :

Daehyunviz
the four consecutive numbers are 51, 53, 55, and 57..
solutions:
let these as the four consecutive no.s:
2n+1, 2n+3, 2n+5, 2n+7

then, substitute:
2(2n+1 + 2n+3) - (2n+5 + 2n+7)=96
8n+8-4n-12=96
n=25

substitute 25 to 2n+1, 2n+3, 2n+5,and 2n+7, and you will get 51, 53, 55, and 57.