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y +1/y2-1 - y/y+1=
What is the answer and explain

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Riza1viz
[tex]\frac{y +1}{y^2-1 } - \frac{y}{y+1} =\frac{y +1}{(y -1)(y+1) } - \frac{y}{y+1} =\frac{y+1 -y(y-1)}{(y-1)(y+1)}=\\\\=\frac{y+1 -y^2+y }{(y-1)(y+1)}= \frac{ -y^2+2y+1}{(y-1)(y+1)}[/tex]