Answered

If x^2-y^2=4 and x+y=12 find the value of x-y

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Mlcparra16viz
Since [tex]( a^{2} - b^{2} )= (a+b)(a-b)[/tex] then

[tex] x^{2} - y^{2} =12(x-y)=4[/tex]
[tex]x-y= \frac{1}{3} [/tex]
Riza1viz
[tex] x^2-y^2=4 \\ x+y=12 \\\\(x+y)(x-y)=4 \\\\12(x-y)=4 \ \ /:12\\\\x-y=\frac{4}{12}\\\\x-y=\frac{1}{3} \\ \\ \\ a^2-b^2=(a+b)(a-b)[/tex]