find the total surface area and the volume of a closed cylindrical container with radius 66 cm and a height of 25 cm

Sagot :

The surface area of a cylinder is [tex]2 \pi rh+2 \pi r^{2} [/tex] because a cylinder is a rectangle when unfolded plus the area of the two circles.

[tex]2(3.14)(66)(25)+2(3.14)( 66^{2} )=10,362+27,355.68=37,717.68[/tex]

So the surface area is [tex]37,717.68[/tex] [tex]cm^{2} [/tex]

The volume of a cylinder is [tex] \pi r^{2} h[/tex]

[tex](3.14)( 66^{2} )(25)=341,946[/tex]

So the volume is [tex]341,946[/tex] [tex]cm^{2} [/tex]