[tex] x^{2} +3X-2+ 2x^{2} +4= x^{2} -4 x^{2} -4[/tex]
[tex]2 x^{2} +x+2=-3 x^{2} -4[/tex]
[tex]5 x^{2} +x+6[/tex]=0
(5x+6)(x-1) =0
[tex]5x+6[/tex]
[tex]5x=-6[/tex]
[tex]x= \frac{-6}{5} [/tex]
[tex]x-1[/tex]
[tex]x=1[/tex]
consider the positive value which is 1 and not -6/5