Nickahviz
Answered

[tex] \frac{-m ^{2} }{5-m}+ \frac{25}{5-m} [/tex]

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Jameskino25viz
[tex] \frac{- m^{2} }{5-m}+ \frac{25}{5-m} \\ \\ = \frac{- m^{2}+25 }{5-m} \\ \\ = \frac{-( m^{2}-25) }{5-m} \\ \\ = \frac{-(m+5)(m-5)}{5-m} \\ \\ =- \frac{-(m+5)(m-5)}{m-5} \\ \\= m+5 [/tex]
Riza1viz
[tex]\frac{-m ^{2} }{5-m}+ \frac{25}{5-m} \\\\5-m\neq 0\\m\neq 5\\D=R\setminus \left \{ 5 \right \}\\\\ \frac{-m ^{2} }{5-m}+ \frac{25}{5-m}= \frac{25-m ^{2} }{5-m}=\frac{ (5-m)(5+m) }{5-m}= 5+m[/tex]