If the amount of mercury in a polluted lake is 0.5 g Hg/ml. What is the total mass in kg of mercury in the lake ? The lake has a surface area of 100 sq. m and an average depth of 20ft
We are given the Density: 0.5 g / mL and the Volume: (100 m^2)(20 ft)(12 in / 1 ft)(2.54 cm / 1 in)(1 m / 100 cm) = 609.6 m^3. We find the mass using the formula: D = M/V --> 0.5 g/mL = M / (609.6 m^3) --> M = 304.8 g.
