Sagot :
[tex] \frac{2}{9} + 3 \frac{6}{15} = 3 \frac{10+18}{45} = 3 \frac{28}{45} [/tex]
2/9+3 6/15=n
dissimilar to similar
2/9=10/45
3 6/15=3 18/45
so that it become
10/45+3 18/45= 3 28/45
dissimilar to similar
2/9=10/45
3 6/15=3 18/45
so that it become
10/45+3 18/45= 3 28/45