[tex]graph : \ f(x)=x^2-6x+4 \\ \\ vertex : \ V= (h,k) \\ \\ a = 1, \ \ \ b = -6\\ the \ x-coordinate \ of \ the \ vertex \ is: \\\\ h=\frac{-b}{2a} = \frac{6}{2}=3 \\\\Substituting \ in \ the \ original \ equation \ to \ get \ the \ y-coordinate, \ we \ get:\\ y=3^2-6\cdot 3+4 =9-18+4=-5\\\\The \ vertex \ of \ the \ parabola \ is \ at \ (3,-5) [/tex]
