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what is the answer of x^2+7x+12>0 w/ its graph????????????

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Riza1viz
[tex]x^2+7x+12>0 \\ \\ (x + 3) \cdot (x + 4)>0 \\ \\ the \ roots\ : \\\\ x + 3=0 \ \ \vee x + 4=0\\ x =-3 \ \ \vee x =-4 [/tex]
a > 0 , opens  up  when 

[tex]Answer: \\\\ x \in (-\infty ,-3)\cup (-4,+\infty )[/tex]
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