A bullet was fired with initial velocity of 966 ft/s directly upward, How high is the bullet from its starting point 10.0 s after it was fired? FORMULA PLEASE? :D
You can use the formula X = VoT + (1/2)AT^2, where X is the distance, Vo is the initial velocity, T is the time, A is the acceleration (since this is a free-fall type of problem, you will use -9.8 m/s^2 as your acceleration).
