[tex]ax \cdot x + bx + c = 0 \\ \\ax^2+bx+c =0 \\ \\ This \ is \ a \ quadratic \ equation\\ \\ x =\frac{-b \pm \sqrt{b^2-4ac} }{2a} \\ \\- \ when \ b^2 - 4ac \ is \ positive, \ we \ get \ two \ Real \ solutions \\ \\[/tex]
[tex]- \ when \ b^2 - 4ac \ is \ zero, we \ get \ just \ ONE \ real solution \\\\- \ when \ b^2 - 4ac \ it \ is \ negative \ so \ we \ have \ no \ real \ solution[/tex]
