Answered

a car is seen from a window of the building 40 meters from the ground. if the car is 30 meters from the building, what is the angles of depression of the building?

Sagot :

Riza1viz
[tex]a= 40 \ m , \ \ \ b= 30 \ m \\ \\ tg\alpha =\frac{a}{b}\\\\tg\alpha =\frac{40}{30}=\frac{4}{3}=1.333\\\\\alpha = 53^o[/tex]


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