Daphne1viz
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Eight times the reciprocal of a number when added to the number is 4 more than the number. Find the number. What's the answer? 

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Kaiusviz
We let x be the number. We write: [tex]8( \frac{1}{x}) + x = 4 + x [/tex]. We now multiply both sides of the equation by x to eliminate the fraction: [tex]x [( \frac{8}{x}) + x = 4 + x] \\ 8 + x^{2} = 4x + x^{2} \\ 8 = 4x \\ 2 = x[/tex]