Jonaleeviz
Answered

 factor the following expression ax-ay-by+bx

Sagot :

Kaiusviz
We first group the similar terms; First, by grouping in A and B: A(X - Y) + B(X - Y), Then we see that (X - Y) is similar in both A and B, we separate (X - Y) --> (X - Y)(A + B).
Cheahjimmyviz
  ax-ay-by+bx
=  a(x-y)+b(x-y)        /     -by+bx    =  +(bx-by)
= (x-y)(a+b)          by grouping