An Object Is Projected Directly Upward From The Ground. After T seconds, Its Distance In Feet Above The Ground Is S= 144t - 16t(squared). After How Many Seconds Will The Object Be 128 Feet Above The Ground
Since we are given the formula: S = 144T - 16T^2, we substitute 128 ft in S to find T: 128 = 144 - 16T^2 --> 16(T^2 - 9T + 8) = 0 --> T^2 - 9T + 8 = 0 --> (T - 8)(T - 1) = 0. T = 1 s and 8 s.
