Johannesanhelaviz
Answered

what is the answer of √27y³

Sagot :

Riza1viz
[tex]\sqrt{ 27y^3}\\y\geqslant 0\\\\\sqrt{ 27y^3}=\sqrt{9\cdot 3\cdot y^2\cdot y}=\sqrt{9 }\cdot \sqrt{y^2}\cdot \sqrt{ 3y }=3y\sqrt{3y}[/tex]