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find the value of k so that the graph of y=(x-2)^2+k will pass through the point (5,12)

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Riza1viz
[tex] (5,12) \\ \\x=5 ,\ \ y=12 \\\\ y=(x-2)^2+k \\ \\ 12=(5-2)^2+k \\ \\12=3^2+k\\\\12=9+k \\ \\k=12-9\\\\k=3\\ \\y=(x-2)^2+3 [/tex]

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