Find the radius of a circle in which a 59-foot chord subtends an angle of 12° at the center.

Sagot :

*draw an isoscles triangle with the bottom side be equal to 59 ft and the angle opposite that side be equal to 12° *bisect the angle 12° into 6° angles *divide the bottom side into two (29.5 ft) *note: the two equal sides of the isosceles triangles are the radii of the circle To solve the radius: sin6° = (29.5 ft / radius) radius = 29.5 ft / sin6° radius = 283.18 ft