Moiraleighginerviz
Answered

REDUCE

4x+4 over 2xcube + 2

Sagot :

Jacobash17viz
4x+4
2x^3+2

2x^-1+2

Final answer: [tex] \frac{2}{2x} [/tex]
Kaiusviz
(4x + 4)/(2x^3 + 2) = 4(x+1) / 2(x^3 + 1) *expanding x^3 + 1 = 4(x+1) / 2(x + 1)(x^2 - x + 1) *cancelling similar terms = 2 / (x^2 - x + 1)