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What is the solution: (9x+2)(4x^2+35x-9)=0 ?

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[tex](9x+2)(4x^2+35x-9)=0\\\\9x+2=0\\9x=-2\\x=-\frac29\\or\\4x^2+35x-9=0\\\Delta=1225+144=1369\ \ \sqrt{\Delta}=37\\x_1=\frac{-35-37}{2 \cdot 4}=-9\\\\x_2=\frac{-35+37}{2\cdot 4}=\frac14\\\\x\in\{-9,-\frac29,\frac14\}[/tex]