Jane92viz
Answered

a rectangular lot has an area of 240m^2.what is the width of the lot of it requires 64m of fencing materials enclose it?

Sagot :

JthanSCOUTviz
x-width
y-length 
xy=240 
2x+2y=64


xy=240 (1,240) (2,120) (3,80) (4,60) (5,48) (6,40) (8,30) (10,24) (12+20=32)
(2x+2y=64)/2
x+y=32

So x(width) and y(length) could either be 12 or 20. Since the length width relationship is not given.