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Answered

sum and difference of two cubes... factoring

27a^3+ 8b^3=

a^6- 27=

8m^3- 27y^3

tnx tnx tnx in advance :)

Sagot :

Cheahjimmyviz
27a³+8b³  = 3³a³+2³b³ = ( 3a+2b)(9a²-6ab+4b²)
a⁶-27 =( a²)³ -3³           =      ( a²-3)(a⁴+3a² +9)
8m³-27y³ = 2³m³- 3³y³  =   (2m-3y)(4m²+6my+9y²)
the pattern is
           a³+b³  =  (a+b)(a²-ab+b²)
           a³- b³  =  (a-b)(a²+ab+b²)


 


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