What three consecutive number can be added to get a sum of 123?

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Math

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What three consecutive number can be added to get a sum of 123?

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ANSWER:

40, 41, 42

EXPLANATION:

Let the first consecutive number be x

Let the second consecutive number be x + 1

Let the third consecutive number be x + 2

Since it's a sum, the numbers must be added

x + (x + 1) + (x + 2) = 123

remove the parenthesis

x + x + 1 + x + 2 = 123

add all the like terms

x + x + x + 1 + 2 = 123

3x + 3 = 123

subtract both sides by 3

3x + 3 - 3 = 123 - 3

3x = 120

divide both sides by 3

[tex]\frac{3x}{3} =\frac{120}{3}[/tex]

x = 40

First consecutive number = x

Second consecutive number = x + 1

Third consecutive number = x + 2

substitute the value of x in the expressions

x = 40

x + 1 = 40 + 1

= 41

x + 2 = 40 + 2

= 42

So the three consecutive numbers are 40,41, and 42

Checking:

40 + 41 + 42 = 123

81 + 42 = 123

123 = 123

Thus, 40,41, and 42 are the three consecutive number can be added to get a sum of 123

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