Sienaviz
Answered

A common foodstuff is found to contain .00125% iron. The serving size is 87.0 grams. If the recommended daily allowance is 18mg of iron, how many servings would a person have to eat to get 100% of the daily allowance of iron? 

Sagot :

AnneCviz
87g x 0.0000125 = 0.0010875g = 1.0875mg
There are 1.0875mg of iron per serving.

18mg ÷ 1.0875mg = 16.55

A person needs to eat 16.55 servings to get 100% of recommended daily allowance of iron.