let l = length
of pathway
&
w = width of of pathway
then
2x + 2y = 90 > 2(x+y) =90 > x+y = 45
> perimeter of rectangle
x = 45-y
and
xy = 350 >
area of rectangle
( 45-y)(y) = 350
45y-y² -350 = 0
/ . -1
y² - 45y +350 = 0
( y -10)(y-35) = 0
y = 10 or y = 35
so the
length is 35m &
the width is 10m