Sagot :
N203
N=14,0=16
Mr N2O3
=(AI N x Ar N)+(AI O x Ar O)
=(2 x 14) + (3 x 16)
=28+48
=76
N=14,0=16
Mr N2O3
=(AI N x Ar N)+(AI O x Ar O)
=(2 x 14) + (3 x 16)
=28+48
=76
N2O3
N=14
O=16
N= 14 X 2 = 28
O= 16 X 3 = 48
Add the sum Of N and O
28 + 48 = 76 g/mol
N=14
O=16
N= 14 X 2 = 28
O= 16 X 3 = 48
Add the sum Of N and O
28 + 48 = 76 g/mol