Ryanryanviz
Answered

Solve inequality: |3x+1|>_5x-1

Sagot :

Bituinviz
3x+1<0
3x<-1
x<-1/3

1)
for x<-1/3
-(3x+1)≥5x-1
-3x-1-5x≥-1
-8x≥0  /:(-8)
x≤0
x∈(-∞,-1/3)

2)
for x≥-1/3
3x+1≥5x-1
3x-5x≥-1-1
-2x≥-2  /:(-2)
x≤1
x∈<-1/3,1>

x∈(-∞, 1>