Vineselena98viz
Vineselena98viz
Math
Answered
4a²b²c² + 12³a³b³c³ =?
common monomial factor.
Sagot :
Smagellajannaviz
Smagellajannaviz
Answer:
a
2
b
2
c
2
⋅
4
(
1
+
432
a
b
c
)
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