Step 1: List the given values.
[tex]\begin{aligned} & P_1 = \text{2.5 atm} \\ & V_1 = \text{55.0 L} \\ & P_2 = \text{1.5 atm} \end{aligned}[/tex]
Step 2: Calculate the final volume by using Boyle's law.
[tex]\begin{aligned} P_1V_1 & = P_2V_2 \\ P_2V_2 & = P_1V_1 \\ \frac{P_2V_2}{P_2} & = \frac{P_1V_1}{P_2} \\ V_2 & = \frac{P_1V_1}{P_2} \\ & = \frac{(\text{2.5 atm})(\text{55.0 L})}{\text{1.5 atm}} \\ & = \boxed{\text{91.7 L}} \end{aligned}[/tex]
Hence, the volume is 91.7 L.
[tex]\\[/tex]
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