Answered

A jeepney from rest accelerates uniformly over a time of 3.5 s and covers a distance of 15 meters. determine the acceleration of the jeepney

Sagot :

Alexnicoleviz

Answer:

2.44 m/s^2

Explanation:

The initial velocity of the Jeep u = 0Acceleration a = ?time of journey t = 5.21 sec.distance covered s = 110 ms = ut + (1/2)at^2

15=0+ (1/2) a x3.5 x 3.5

a = (15 x 2)/(3.5 x3.5)

a= 30/12.25 = 2.44 m/s^2