[tex]\large \rm {\color{blue}{Question:}}[/tex]
What is the kinetic energy of a 0.01lbm bullet travelling 2000 ft/s relative to the barrel of the gun it has left?
[tex]\small \rm {\color{red}{Answer:}}[/tex]
K.E = 20,000 ft/s J
Explanation:
To find the K.E/Kinetic Energy you have to use this formula.
How to solve?
1.)Identify the given
Mass of the bullet is 0.01 lbm, and the velocity/speed of the bullet is 2000 ft/s.
2.)Solve
- K.E = ½mv²
- K.E =½0.01 lbm (2,000 ft/s)²
- K.E =½ 0.01 lbm (4,000,000 ft/s)
- K.E = ½40,000 lbmft/s
- K.E = 20,000 lbmft/s
Therefore, the Kinetic Energy of the bullet is 20,000 lbmft/s.
Hope it helps :D
By : セン
