Answer:
1.the momentum of a 1200-kg car with a velocity of 25 m/s is 30000 kg-m/s.
2.Momentum responsible for the vertical velocity of the discus is obtained during the second half of the second single-support phase and the first half of the delivery phase. Rotary momentum is stored in the thrower's body and is expressed as rotation of the body.
3.Speed of the object (v) = 2 m/s. Kinetic Energy (K.E) = ½ mv2. = ½ (10)(2)2 ⇒ 20 joules. The kinetic energy of the object is 20 J.
Explanation:
correct me if im wrong po^^