Sagot :
Answer:
2.07 mol
Explanation:
Sample 1: n₁ = 0.75 mol, V₁ = 7.25 L
Sample 2: n₂ = ? mol, V₂ = 20 L
For gases at constant pressure and temperature (Avogadro's law): n₁/n₂ = V₁/V₂
Then, n₂ = n₁ × (V₂/V₁)
No. of moles in the 20 L sample, n₂ = (0.75 mol) × (20/7.25) = 2.07 mol