A man dives from a 35 m high cliff and reaches the water with final vertical velocity of 45m/s. How much time has elapsed before he reached the water?​

Sagot :

Basic Formula

The basic formula for calculating acceleration is:

[tex]a = \frac{v - v_0}{t}[/tex]

a = acceleration

V = final velocity

Vo = initial velocity

t = time

Derived Equation

From the above equation, we can derive the formula for calculating the time:

[tex]t = \frac{v-v_0 }{a}[/tex]

Acceleration Due to Gravity

Since the man is diving, we can assume that the acceleration due to gravity is 9.8m/s^2.

Solving for Time

As such, we can solve for time as follows:

[tex]t = \frac{45m/s - 0 m/s}{9.8 m/s^{2} }[/tex]

[tex]t = \frac{45m/s}{9.8m/s^{2} }[/tex]

[tex]t = 4.59 s[/tex]

The time elapsed is 4.59 seconds.