Answer:
Vx = 1.50 m/s ; height of table = ? ; dx = 0.70 m ; v_final = ?
Formula for horizontal motion
dx = Vx * t_fall
0.70 m = 1.50 m/s * t_fall
t_fall = 0.70 m / 1.50 m/s
t_fall = 0.467 seconds
Solving for the height of the table top
height = 1/2 * g * t_fall^2
height = 4.9 m/s^2 * (0.467 s)^2
height = 4.9 m/s^2 * 0.218 s^2
height = 1.068 meters
Solving for the marble's velocity before hitting the floor
The marble's velocity has two components that must be combined by using the Pythagorean theorem
v^2 = Vx^2 + Vy^2
v^2 = (1.50 m/s)^2 + Vy^2
v^2 = 2.25 (m/s)^2 + g * t_fall
v^2 = 2.25 (m/s)^2 + 9.8 m/s^2 * 0.467 s
v^2 = 2.25 (m/s)^2 + (4.577 m/s)^2
v^2 = 2.25 (m/s)^2 + 20.95 (m/s)^2
v^2 = 23.2 (m/s)^2
v = √(23.2) (m/s)^2
v_final = 4.82 m/s at 65 degrees from the horizontal
Explanation:
hope it help
