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A heat engine can produce constant pressure of 3.69 atm from 9.89 L-atm. What is the expected change in volume from this kind of heat engine?

will appreciate your valid answer, ty​

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Answer:

Formula

[tex]v1 = l \: atm \: \times \frac{v2 \: l \: atm \: }{v1 = l \: atm}[/tex]

Explanation:

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