Maximum horizontal range of projectile formula

Sagot :

Answer:

Maximum Range of Projectile

Now that the range of projectile is given by R = u 2 sin ⁡ 2 θ g , when would be maximum for a given initial velocity . Well, since is a constant, for a given , depends on ⁡ and maximum value of is . So, R m a x = u 2 g and it is the case when θ = 45 ∘ because at θ = 45 ∘ , ⁡ 2 θ = 1 .