Answer:
The probability of having:
1. a 10
Solution:
R {1,2,3,4,5,6,7,8,9,10,11,12}
There are 12 samples all in all and
P[10]= 1/12.
Therefore, a. 1/12 is the answer.
2. a 13
In the set there is no 13 so, the P[13] is 0.
Therefore,f. 0/12 or 0.
3. odd number
Solution:
In the set the odd number are {1,3,5,7,9,11}.
Therefore, P[odd number]=1/12+1/12+1/12+1/12+1/12+1/12=6/12 or 1/2.
Letter d. 6/12 or 1/2 is the answer.
4. even number
Solution:
In the set the even number are {2,4,6,8,10,12}.
Therefore, P[even number]=1/12+1/12+1/12+1/12+1/12+1/12=6/12 or 1/2.
Letter d. 6/12 or 1/2 is the answer.
5. an odd number divisible by 3
Solution:
In the set the odd number divisible by 3 are {3,9}.
Therefore,the P[odd number divisible by 3] = 1/12+1/12=2/12 or 1/6.
Letter b. 2/12 or 1/6 is the answer.
6 an even number divisible by 3
Solution:
In the set the even number divisible by 3 are {6,12}.
Therefore,the P[even number divisible by 3] = 1/12+1/12=2/12 or 1/6.
Letter b. 2/12 or 1/6 is the answer.
Step-by-step explanation:
