Answer:
Let
- Statement of the given problem,
- A ball was thrown horizontally from the edge of the table at a velocity of 4 m/s. If the table is 2 m high, what is the ball’s velocity just before it hits the ground?
- V denotes the required ball’s velocity (in m/s) just before it hits the ground.
- M denotes the mass (in kg) of the given ball.
- According to conservation principle of mechanical energy,
- from above data we get following relation,
- Final (PE + KE) of the ball = Initial (PE + KE) of the ball
- or 0 + (1/2)*M*V^2 = M*g*2 + (1/2)*M*4^2 [g = gravitational acceleration]
- or V^2 = 4*g + 16
- or V^2 = 4*9.81 + 16 [g = 9
Explanation:
BRAINLIEST IS HIGHLY APPRECIATED
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