Answer:
Solution:
frequency = 6,22,43,29,9
we know that
[tex] mean\frac{sum \: of \: data}{sum \: of \: terms} [/tex]
[tex]mean \frac{6 + 22 + 43 + 29 + 9}{5} [/tex]
[tex] = \frac{6 + 9 + 22 + 28 + 43}{5} [/tex]
[tex] = \frac{108}{5} = 21.6[/tex]
[tex]mean = 21.6[/tex]
[tex] median\frac{(n + 2)}{2} { + }^{4} [/tex]
[tex] = \frac{5 + 1}{2} = \frac{6}{2} = 3[/tex]
so, median is 43
Step-by-step explanation:
Hope it helps
Sorry for incomplete answer
Yan lang kaya masagutan eh..
